r/mathpuzzles • u/TargetLabs • 2d ago

Recreational maths Can you reach 23 using all 5 dice?

Post image

Any order is allowed.
Use each die exactly once.
Parentheses are allowed.
Only +, −, × and ÷ are allowed. No concatenation or exponents.
Exact division only.
No negative numbers.
Not every operation has to be used.

How many solutions can you find?

Please use spoiler tags for solutions:
>!your solution here!<

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2

u/CruCinque_Renzo 2d ago

3 x 4 + 2 + 4 + 5

2

u/James_HN 2d ago edited 2d ago

I was able to find 3.

  1. 4 + 2 + 5 + 4 × 3

  2. 4 + 2 + 4 × 5 - 3

  3. 4 ÷ 2 × 4 + 5 × 3

1

u/pandymen 2d ago

4. 4x4+2x5-3

Most of your solutions use + twice. I thought that we were only supposed to use each operator once.

1

u/OmegaGoo 2d ago

You have multiplication twice.

Anyway, no, it's each number once.

2

u/AnakITB 2d ago

5 x (4+2) - (4+3)

1

u/AnalysisParalysis85 2d ago edited 2d ago

I didn't think to use brackets to get 2 uses of minus.

Edit:

Actually nevermind, I approached these with the idea that each operator can be only used once too.

1

u/AnakITB 2d ago

Yeah, the usage of parentheses just to show my thinking process. Its just shows 30-7, and my brain grouped the last 4 and 3 as 7, hehe

1

u/jaysornotandhawks 2d ago

4 x 2 = 8

8 x 3 = 24

5 - 4 = 1

24 - 1 = 23