r/mathpuzzles • • 3d ago

Stumped on a math puzzle

I've been presented with a math puzzle that I can't seem to solve.  The puzzle is a variation of the old game of "24" that used to come on cards.  There are six input numbers, and 4 operations allowed.  Each input and each operation may only be used once.  Order of operations applies, so multiplication and division are processed before addition and subtraction.  The six inputs are:

6, 9, 11, 12, 25, and 27.

The 4 allowed operations are:

addition, subtraction, multiplication, division.

The puzzle:  Using each input and each operation no more than once, and following the standard mathematical order of operations, find a way to get the result of 12. At least one operation must be used.

What is the solution? Is there a standard way beside brute force to find the solution?

Thanks

2 Upvotes

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3

u/EtiennePumpkin 3d ago

9-12/6x11+25 or 25-12/6x11+9

1

u/StellarisFanatic 3d ago

Thank you! I think I missed the idea of putting a product of 3 inputs in the middle between addition and subtraction.

1

u/[deleted] 3d ago

[deleted]

1

u/FormerPlayer 3d ago

Can't use operations more than once. 

1

u/FormerPlayer 3d ago

Are parentheses allowed? 

(9×11-27)÷6 

1

u/StellarisFanatic 3d ago

Sadly, no. So this answer actually looks like (9x11)-(27÷6)=94.5